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X^2+14X-81=0
a = 1; b = 14; c = -81;
Δ = b2-4ac
Δ = 142-4·1·(-81)
Δ = 520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{520}=\sqrt{4*130}=\sqrt{4}*\sqrt{130}=2\sqrt{130}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{130}}{2*1}=\frac{-14-2\sqrt{130}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{130}}{2*1}=\frac{-14+2\sqrt{130}}{2} $
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